The value of dy/dx at point (1, 0) for the function is 1
Given the function ;
The derivative of y = In(x² + y²)
From the concept of standard integral , d/dx(In(x)) = 1/x
dy/dx = 1/(x² + y²)
Substituting the values of the points into the derivation
Now we have ;
1² + 0² = 1
Therefore, the result is 1.