Question

Which of the following boxes could be used for three each 10 AWG and six each 12 AWG conductors? d. 31/2" deep masonry box e. any of these a. 2-Gang 21/2" deep masonry box b. 1/2" deep 4"-SQ box c. 11/4" deep 411/16"-SQ box 4 Refer to​

Answer 1

To find the resistivity of the second wire, use the formula: ρ2 = ρ1 (R2 / R1). Given ρ1 as 2.65 x 10^-8 Ω.m and R1 as 30 Ω, with R2 being 11 Ω, the resistivity of the second wire, ρ2, is approximately 9.7155 x 10^-9 Ω.m.

Step-by-step explanation:

The student is asking how to find the resistivity of a wire given the resistance and resistivity of another wire with the same length and cross-sectional area. The resistance (R) of a wire is directly proportional to its resistivity (ρ), and since the two wires have the same dimensions, we can set up a ratio using the formula R = ρL/A, where L is the length and A is the cross-sectional area of the wire. Because L and A are the same for both wires, we can ignore them in our calculations.

To find the resistivity of the second wire, we use the formula:

ρ2 = ρ1 (R2 / R1)

Where:

Substituting the known values into the formula:

ρ2 = (2.65 x 10-8 Ω.m) * (11 Ω / 30 Ω)

ρ2 = (2.65 x 10-8 Ω.m) * (0.3667)

ρ2 = 9.7155 x 10-9 Ω.m

The resistivity of the second wire is therefore approximately 9.7155 x 10-9 Ω.m.