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Given that seawater contains ~28.0 g of NaCl per liter, what is the molarity of sodium chloride in sea water? **Molar Mass of NaCl = 58.443 g/mol**

User Davy Meers
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Final answer:

The molarity of sodium chloride in sea water can be calculated by dividing the number of moles Molarity = Moles of NaCl / Volume (in liters) Molarity = (Mass of NaCl / Molar mass of NaCl) / Volume (in liters) Let's substitute the given values and calculate the molarity: The molarity of sodium chloride in seawater is 0.479 M.

Step-by-step explanation:

The molarity of sodium chloride in sea water can be calculated by dividing the number of moles of sodium chloride (NaCl) by the volume of the solution in liters. Given that seawater contains 28.0 g of NaCl per liter, we can find the moles of NaCl by dividing the mass of NaCl by its molar mass. The molar mass of NaCl is 58.443 g/mol. So, the molarity of sodium chloride in seawater is: Molarity = Moles of NaCl / Volume (in liters) Molarity = (Mass of NaCl / Molar mass of NaCl) / Volume (in liters) Let's substitute the given values and calculate the molarity: Molarity = (28.0 g / 58.443 g/mol) / 1 L = 0.479 M.

The molarity of sodium chloride in sea water can be calculated by dividing the number of moles Molarity = Moles of NaCl / Volume (in liters) Molarity = (Mass of NaCl / Molar mass of NaCl) / Volume (in liters) Given that seawater contains 28.0 g of NaCl per liter, we can find the moles of NaCl by dividing the mass of NaCl by its molar mass. Let's substitute the given values and calculate the molarity: The molarity of sodium chloride in seawater is 0.479 M.

User Mauro Delrio
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