Final answer:
The osmolarity of sodium chloride in seawater, where there is approximately 28.0 g of NaCl per liter, is about 0.958 osmoles/L when considering that NaCl dissociates into two particles.
Step-by-step explanation:
The question is about calculating the osmolarity of sodium chloride in sea water, given that sea water contains approximately 28.0 g of NaCl per liter. To calculate osmolarity, which is the total concentration of all the solute particles in a solution, we need to consider that each unit of NaCl will dissociate into two particles (Na+ and Cl-).
To begin with, we convert the mass of NaCl to moles using the molar mass of NaCl (58.443 g/mol):
Moles of NaCl = 28.0 g / 58.443 g/mol = 0.479 moles/L
Since each mole of NaCl dissociates into 2 moles of particles:
Osmolarity of NaCl = 2 x 0.479 mol/L = 0.958 osmoles/L