Final answer:
A K-DUR 20 mEq tablet contains 1490 mg of Potassium Chloride (KCl). One mEq is 74.5 mg of KCl, and since the tablet is 20 mEq, it is simply 20 times that quantity.
Step-by-step explanation:
The amount of Potassium Chloride (KCl) in a K-DUR 20 mEq tablet can be calculated knowing that 'mEq' stands for milliequivalents which is a measure of the amount of a substance based on the number of ions or electrons that substance can provide. One equivalent of KCl (which disassociates into K+ and Cl- ions) equals the molar mass of KCl divided by its valency, which for KCl is 1. Therefore, 1 Eq is equal to 74.5 g of KCl. Accordingly, 1 mEq is 1/1000 of an Eq, which is 74.5 mg.
To find out how many milligrams there are in 20 mEq, we multiply 74.5 mg by 20, which gives us 1490 mg. Hence, there are 1490 mg of KCl in a K-DUR 20 mEq tablet.