Question

Please help me!! Thank you!!

Answer 1

`Solution,\\PQ = √((1-3)^2+(3-1)^2) = √(2^2+2^2) = √(8) = 2√(2) \\P'Q' = √((3-9)^2+(9-3)^2) = √(6^2+6^2) = √(72) = 6√(2)\\Also,\\RQ = √((1-3)^2+(1-1)^2) = √(2^2) = 2\\R'Q' = √((3-9)^2+(3-3)^2) = √(6^2) =6\\Again,\\PR = √((1-1)^2+(3-1)^2) = √(2^2)=2\\P'R' = √((3-3)^2+(9-3)^2) = √(6^2) = 6\\Here, P'R' = 3PR, P'Q'=3PQ ~and~ Q'R'=3RQ~\\In~other~words~each~side~of~triangle~P'Q'R' ~is~three~times~the~length~of~triangle~PQR.\\`
`So,~the~algebraic~rule~of~diliation(enlargement)~is~(x,y)----(3x,3y)`

If my answer did not help you, comment below but please don't delete it.