Final answer:
To find the milliequivalents of Na+ and Cl- in 0.9% NaCl solution, convert the mass of NaCl to moles using its molar mass, then multiply by 1000 to convert to milliequivalents since there is a 1:1:1000 relationship between moles, equivalents, and milliequivalents.
Step-by-step explanation:
To calculate how many milliequivalents of Na+ and Cl- are in 0.9% NaCl (Normal Saline), we start with understanding the concentration. A 0.9% solution of NaCl means that there are 0.9 grams of NaCl in 100 mL of solution, or 9 grams in 1000 mL (1 litre) of solution. The molar mass of NaCl (sodium chloride) is given as 58.443 grams per mole. Hence, the number of moles of NaCl in 1 litre can be calculated as:
moles of NaCl = mass of NaCl / molar mass of NaCl = 9 g / 58.443 g/mol
One mole of NaCl dissociates into one mole of Na+ and one mole of Cl-. Because one equivalent of Na+ or Cl- is equal to one mole of Na+ or Cl-, the milliequivalents will be the same as the moles, but in millimoles since we are working with milliequivalents.
Therefore, the number of milliequivalents of Na+ and Cl- per litre of solution is:
milliequivalents of Na+/Cl- = moles of NaCl * 1000 = (9 g / 58.443 g/mol) * 1000 mEq/L