Final answer:
To calculate the grams of C6H12O6 in the solution, you can use the equation: grams of C6H12O6 = volume of solution (L) x molarity (mol/L) x molar mass of C6H12O6 (g/mol). In this case, there are approximately 13.5 grams of C6H12O6 in 300 mL of a 0.25 M solution.
Step-by-step explanation:
To calculate the grams of C6H12O6 in the solution, we need to use the equation:
grams of C6H12O6 = volume of solution (L) x molarity (mol/L) x molar mass of C6H12O6 (g/mol)
In this case, the volume of the solution is 300 mL, which is equivalent to 0.3 L. The molarity of the solution is 0.25 M. The molar mass of C6H12O6 is 180.18 g/mol.
Using the equation, we can calculate:
grams of C6H12O6 = 0.3 L x 0.25 mol/L x 180.18 g/mol = 13.5145 g
Therefore, there are approximately 13.5 grams of C6H12O6 in 300 mL of a 0.25 M solution.