Final answer:
In a 0.15 M solution of K2SO4, the concentration of K+ ions is 0.30 M because each formula unit of K2SO4 dissociates into 2 K+ ions.
Step-by-step explanation:
The question asks about the concentration of K+ ions in a 0.15 M solution of K2SO4. To find the concentration of potassium ions, you need to recognize that each unit of potassium sulfate dissociates into 2 potassium ions (K+) and 1 sulfate ion (SO42-). Therefore, in a 0.15 M K2SO4 solution, the concentration of K+ ions will be twice that of the K2SO4 because there are 2 moles of K+ for every mole of K2SO4. The calculation would be as follows:
Concentration of K+ = 2 × Concentration of K2SO4 = 2 × 0.15 M = 0.30 M.
Thus, the concentration of K+ in the solution is 0.30 M.