Final answer:
Recombinants in bacteriophage are produced through a process that requires two crossovers to integrate and then resolve donor DNA with phage DNA.
Step-by-step explanation:
To produce recombinants in phage, two crossovers are required. This is because the first crossover integrates the donor DNA into the phage's genetic material, and the second resolves the recombinant DNA so that each resulting DNA molecule is a mixture of virus and bacterial genes. This is different from bacterial conjugation, where the transfer of an F plasmid (or fertility plasmid) can be involved in transferring genetic material between bacterial cells.