Question

The cross GE/ge × ge/ge produces the following progeny: GE/ge 404; ge/ge 396; gE/ge 97; Ge/ge 103. From these

data, one can conclude that there are ________ map units between the G and E loci.
A) 15 B) 25 C) 10 D) 5 E) 20

Answer 1

There are e. 20 map units between the G and E loci.

Step-by-step explanation:

The cross between GE/ge and ge/ge produces 404 GE/ge progeny, 396 ge/ge progeny, 97 gE/ge progeny, and 103 Ge/ge progeny. Based on these results, we can determine the recombination frequency between the G and E loci.

Recombination frequency is calculated by dividing the number of recombinant progeny (gE/ge and Ge/ge) by the total number of progeny. In this case, the recombination frequency is (97 + 103) / (404 + 396 + 97 + 103) = 0.20, or 20%.

One map unit corresponds to a recombination frequency of 1%, so we can conclude that there are e. 20 map units between the G and E loci.