Final answer:
The next greatest positive integer that has a remainder of 3 when divided by 6 and a remainder of 6 when divided by 7 is 69, as it is the only option that satisfies both conditions.
Step-by-step explanation:
To find the next greatest positive integer that has a remainder of 3 when divided by 6 and a remainder of 6 when divided by 7, we need to look for a number that satisfies both conditions. These types of problems are commonly solved using methods from number theory, such as the Chinese Remainder Theorem or systematic checking. However, since we have a list of options, we can simply check each one.
Let's analyze the options provided:
- 39 divided by 6 gives a quotient of 6 and a remainder of 3, and 39 divided by 7 gives a quotient of 5 and a remainder of 4. So, 39 doesn't satisfy the second condition.
- 48 divided by 6 gives a quotient of 8 and a remainder of 0, and 48 divided by 7 gives a quotient of 6 and a remainder of 6. While the remainder when divided by 7 is correct, it's not when divided by 6.
- 51 divided by 6 gives a quotient of 8 and a remainder of 3, and 51 divided by 7 gives a quotient of 7 and a remainder of 2. So, 51 doesn't satisfy the second condition either.
- 69 divided by 6 gives a quotient of 11 and a remainder of 3, and 69 divided by 7 gives a quotient of 9 and a remainder of 6. This number satisfies both conditions and is the correct answer.
- 90 divided by 6 gives a quotient of 15 and a remainder of 0, and 90 divided by 7 gives a quotient of 12 and a remainder of 6. Again, only the remainder when divided by 7 is correct.
Therefore, the next greatest positive integer after 27 that has a remainder of 3 when divided by 6 and a remainder of 6 when divided by 7 is 69.