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Help me solve this math equation!

Help me solve this math equation!-example-1
User Derickito
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1 Answer

1 vote

The equation 36x² + 4y² - 288x + 16y + 448 = 0 to standard form is (x - 4)² + (y + 2)²/9 = -20

Converting the equation to standard form

From the question, we have the following parameters that can be used in our computation:

36x² + 4y² - 288x + 16y + 448 = 0

Rewrite as

36x² + 4y² - 288x + 16y + 448 = 0

Group the equation by the variables

36x² - 288x + 4y² + 16y = -448

So, we have

36(x² - 8x) + 4(y² + 4y) = -448

Complete the square on x and y

So, we have

36(x - 4)² + 4(y + 2)² = -448 + 16 - 288

This gives

36(x - 4)² + 4(y + 2)² = -720

Next, we divide through by 36

(x - 4)² + (y + 2)²/9 = -20

Hence, the equation is (x - 4)² + (y + 2)²/9 = -20

User Sandra Rossi
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