Question

Use the standard reaction enthalpies given below to determine ∆ H ° r x n for the following reaction: 2 N O ( g ) + O 2 ( g ) → 2 N O 2 ( g ) GIVEN: N 2 ( g ) + O 2 ( g ) → 2 N O ( g ) △ H ° r x n = + 183 k J

Answer 1

The standard reaction enthalpy for the reaction 2NO(g) + O2(g) → 2NO2(g) is directly given as -114.1 kJ, and no further calculations are required to determine it since the question provides this specific reaction enthalpy.

Step-by-step explanation:

To determine the standard reaction enthalpy (Δ H°rxn) for the reaction 2NO(g) + O2(g) → 2NO2(g), we can use the reaction enthalpies given and Hess's Law. The reactions provided and their reaction enthalpies are:

• N2(g) + O2(g) → 2NO(g), Δ H°rxn = +183 kJ
• 2NO(g) + O2(g) → 2NO2(g), Δ H° = -114.1 kJ

Since the desired reaction is the formation of 2NO2(g) directly from 2NO(g) and O2(g), the second equation provided is already directly depicting the reaction for which we want to find the enthalpy change. Therefore, no additional steps are required; the Δ H°rxn is simply -114.1 kJ for the formation of 2NO2(g) from 2NO(g) and O2(g).