Question

Maximize p = x 2y subject to x 5y ≤ 11 6x y ≤ 8 x ≥ 0, y ≥ 0.

Answer 1

The maximum value of the objective function P = x + 2y is 5

How to find the maximum value of the objective function

From the question, we have the following parameters that can be used in our computation:

P = x + 2y

Subject to:

x + 5y ≤ 11

6x + y ≤ 8

x ≥ 0, y ≥ 0.

Express the constraints as equation

So, we have

x + 5y = 11

6x + y = 8

When solved for x and y, we have

x + 5y = 11

30x + 5y = 40

So, we have

29x = 29

x = 1

Next, we have

6(1) + y = 8

This means that

y = 2

Recall that

P = x + 2y

So, we have

P = 1 + 2 * 2

Evaluate

P = 5

Hence, the maximum value of the objective function is 5

Question

Maximize P = x + 2y subject to x + 5y ≤ 11 and 6x + y ≤ 8

x ≥ 0, y ≥ 0.