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What is the final temperature (in °C) of 870.1 g of water (specific heat = 4.184 J/g・ °C) at 24.20 °C that absorbed 950.0 J of heat?

User Jawnnypoo
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1 Answer

7 votes

Final answer:

The final temperature of the water is 31.2°C.

Step-by-step explanation:

To find the final temperature, we can use the equation:

q = mcΔT

where q is the heat absorbed by the water, m is the mass of the water, c is the specific heat of water, and ΔT is the change in temperature.

Plugging in the values:

q = 950.0 J, m = 870.1 g, c = 4.184 J/g・°C, and ΔT = final temperature - initial temperature = T f - 24.20°C.

Rearranging the equation to solve for T f:

T f = (q / mc) + 24.20°C

Substituting the values:

T f = (950.0 J / (870.1 g * 4.184 J/g・°C)) + 24.20°C

Simplifying the expression gives the final temperature T f = 31.2°C.

User L Co
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