Question

Two spheres each carry a charge of \[1\times 10^{-7}\,\text{C}\]. Their centers are separated by \[0.7\,\text{m}\].

Calculate the magnitude of the force between these two charged objects.

Answer 1

The magnitude of the force between two charged spheres, given that each charge is 1 \times 10^{-7} C and they're separated by 0.7 m, can be calculated using Coulomb's Law and results in a force of
`1.84 * 10^(-4) N`

Step-by-step explanation:

To calculate the magnitude of the force between two charged spheres, we can apply Coulomb's Law:

`F = k \cdot (|q1 \cdot q2|)/(r^2)`

where:

• F is the force between the charges,
• k is Coulomb's constant (≈ 8.99 \times 10^9 Nm^2/C^2),
• q1 and q2 are the charges of the spheres (both are 1 \times 10^{-7} C in this case), and
• r is the distance between the centers of the two charges (0.7 m).

Substituting all the values into the formula:

F =
`(8.99 * 10^9 Nm^2/C^2) \cdot ((1 * 10^(-7) C) \cdot (1 * 10^(-7) C))/((0.7 m)^2)`

By calculating, we find:

F =
`8.99 * 10^9 * (1 * 10^(-14))/(0.49)`

And this results in:

F =
`1.84 * 10^(-4) N`

Thus, the magnitude of the force between the two charged spheres is
`1.84 * 10^(-4) N`