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For the function​ below, (a) find the​ vertex; (b) find the axis of​ symmetry; (c) determine whether there is a maximum or a minimum value and find that​ value; and​ (d) graph the function.

​f(x)=2x^2+6x+7

User Vibert
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The quadratic function f(x) = 2·x² + 6·x + 7, indicates that the parameters of the graph of the function are;

(a) (-1.5, 2.5)

(b) x = -1.5

(c) Minimum value

(d) Please find attached the graph of the function f(x) = 2·x² + 6·x + 7, created with MS Excel

What is a quadratic function?; A quadratic function is a function of the form f(x) = a·x² + b·x + c, where a ≠ 0, and a, b, and c, are numbers

The x-coordinate of the vertex can be found using the equation;

x-coordinate of vertex = -b/(2·a)

Therefore; x-coordinate of vertex = -6/(2×2)

-6/(2×2) = -3/2

-3/2 = -1.5

The y-coordinate of the vertex is therefore;

f(-1.5) = 2 × (-1.5)² + 6 × (-1.5) + 7

2 × (-1.5)² + 6 × (-1.5) + 7 = 2.5

The y-coordinate of the vertex is; y = 2.5

The vertex is therefore; (-1.5, 2.5)

(b) The axis of symmetry of the quadratic equation of the form; f(x) = 2·x² + 6·x + 7 is the equation x = x-coordinate of the vertex, therefore;

The axis of symmetry is; x = -1.5

(c) The quadratic function f(x) = 2·x² + 6·x + 7, with a positive leading coefficient has a ∪ shape, and therefore has a minimum point

(d) The graph of the function, f(x) = 2·x² + 6·x + 7 can be obtained by calculating the values in the ordered pair and plotting the values on the coordinate plane as follows;

x; -6, -5, -4, -3, -2, -1, 0, 1, 2, 3

y; 43, 27, 15, 7, 3, 3, 7, 15, 27, 43

The above points points can be used to plot the graph of the function f(x) = 2·x² + 6·x + 7 using MS Excel

For the function​ below, (a) find the​ vertex; (b) find the axis of​ symmetry; (c-example-1
User Luca T
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