Question

Last year, Pinwheel Industries introduced a new toy. It cost $ 9300 to develop the toy and $ 30 to manufacture each toy. Fill in the blanks below as appropriate.

Answer 1

Given data:

Cost of develop: $9300

Cost of factory each toy: $30

n is the number of toys

`C=mn+b`

m is the cost of factory each toy

b is the cost of develop

A)

`C=30n+9300`

B) find C when n=1900

`\begin{gathered} C=30(1900)+9300 \\ C=66300 \end{gathered}`

The total cost to produce n=1900 toys is $66300

C) find n when C=42300

`\begin{gathered} 42300=30n+9300 \\ Subtract\text{ 9300 in both sides of the equation:} \\ 42300-9300=30n+9300-9300 \\ 33000=30n \\ \\ \text{Divide both sides of the equation into 30:} \\ (33000)/(300)=(30)/(30)n \\ \\ 1100=n \\ \\ \\ \\ \\ n=1100 \end{gathered}`

With $42300, a total of 1100 toys can