Question

In the reaction S P, if one mole of product (P) has the same free energy as one mole of substrate (S), what is the value for the K¥eq of this reaction? What is the value of the G[infinity]¥? If you started with a 1M solution of S, would it spontaneously react to give any P? What would the concentration of S and P be when the reaction had reached equilibrium?

Answer 1

For the reaction S ⇌ P with an equilibrium constant Keq of 1 and ΔG° of 0, equal concentrations of S and P would exist at equilibrium, starting from a 1M solution of S.

Step-by-step explanation:

In the reaction S ⇌ P, where one mole of product (P) has the same free energy as one mole of substrate (S), the value for the equilibrium constant Keq is 1. This is because when the standard free energy change (ΔG°) for a reaction is zero, the reaction quotient (Q) equals the equilibrium constant (K), and the reaction is at equilibrium with no tendency to shift in either direction. Therefore, the value of ΔG° in this case would also be 0 kJ/mol.

With a starting 1M solution of S, the reaction would not spontaneously proceed in any direction to produce more P, because the free energies of S and P are equal. When the reaction reaches equilibrium, the concentrations of S and P would be equal because Keq is 1, assuming that no other factors like phase differences or changes in the number of gas molecules are involved. This is a theoretical scenario, as real systems may be influenced by external disturbances or may not behave ideally.