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In a reversible reaction at equilibrium, the concentration of R (the reactant) is 3.0 mol/L and the concentration of P (the product) is 0.9 mol/L. At 25°C, what would be the Keq?

A. 3.0
B. 37.5
C. 1.0
D. 1.5
E. 0.3

User Maxim
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1 Answer

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Final answer:

The equilibrium constant Keq for the given reversible reaction at equilibrium is 0.3.

Step-by-step explanation:

The equilibrium constant (Keq) represents the ratio of the mathematical product of the concentrations of the products to the mathematical product of the concentrations of the reactants in a reversible reaction at equilibrium. In this case, [R] = 3.0 mol/L and [P] = 0.9 mol/L.

To calculate Keq, we divide the concentration of the product by the concentration of the reactant. Keq = [P] / [R] = 0.9 / 3.0 = 0.3.

User Vgrafe
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