Final answer:
The horizontal component of the velocity for a water balloon launched at 7.3 m/s at a 25-degree angle is approximately 6.63 m/s, calculated using the formula Vx = V * cos(θ).
Step-by-step explanation:
The question involves calculating the horizontal component of the velocity for a water balloon launched at a certain angle and initial speed, which is a topic in projectile motion. To find the horizontal component (Vx) of the velocity, you can use the formula Vx = V * cos(θ), where V is the initial velocity and θ is the launch angle.
In this case, the initial velocity (V) is given as 7.3 m/s and the angle (θ) is 25 degrees. Plugging these values into the formula gives us:
Vx = 7.3 m/s * cos(25°) = 6.63 m/s (approximately)
Therefore, the horizontal component of the velocity for the water balloon is approximately 6.63 m/s.