To find the molarity of the solution, convert the mass percent to grams, calculate the moles of KOH, and then divide by the volume of the solution. The molarity of the solution is 12.144 M.
To find the molarity of a solution, we need to know the number of moles of solute and the volume of the solution. In this case, we have 750 mL of a 68% (w/v) KOH solution.
Step 1: Convert the mass percent to grams. Since the solution is 68% (w/v), we have 68g KOH in 100 mL of solution. So, in 750 mL, we have 750 x (68/100) = 510 g KOH.
Step 2: Calculate the moles of KOH. The molar mass of KOH is 56.11 g/mol, so the moles of KOH are 510g / 56.11g/mol = 9.108 mol.
Step 3: Calculate the molarity. Since the volume of the solution is 750 mL = 0.75 L, the molarity is 9.108 mol / 0.75 L = 12.144 M.
Complete question is:
1. What is the molarity of the solution with 750 mL of 68% (w/v) KOH?
2. What would be the boiling point of the solution with 750 mL of 68% (w/v) KOH, given a molar mass of 56.11 g/mol for
KOH?
3. What is the osmolarity of the solution with 750 mL of 68% (w/v) KOH, considering the molar mass of KOH as 56.11
g/mol?