47,864 views
21 votes
21 votes
What is the area of a polygon with vertices of (-2, -4), (4, -4), (4, 4), and (-5, 4)?thank you ! :)

What is the area of a polygon with vertices of (-2, -4), (4, -4), (4, 4), and (-5, 4)?thank-example-1
User Ryaner
by
3.1k points

1 Answer

18 votes
18 votes

Given:

The vertices of the polygon are (-2, -4), (4, -4), (4, 4), and (-5, 4).

Required:

We need to find the area of the given polygon.

Step-by-step explanation:

Mark the points (-2, -4), (4, -4), (4, 4), and (-5, 4) and join them by line.

We get the polygons ABCD is a trapezoid.

BD is height of the trapezoid.

Let AB=a, CD=b, and BD=h.

Use the distance formula to find the measure of length.


d=√((x_2-x_1)^2+(y_2-y_1)^2)

Consider the points (-5,4) and (4,4).


Substitute\text{ }x_2=4,x_1=-5,y_2=4,\text{ and }y_1=4\text{ in the distance formula.}


a=√((4-(-5))^2+(4-4)^2)
a=√((4+5)^2+0)
a=√(9^2)
a=9units

Consider the points (-2,-4) and (4,-4).


Substitute\text{ }x_2=4,x_1=-2,y_2=-4,\text{ and }y_1=-4\text{ in the distance formula.}


b=√((4-(-2))^2+(-4-(-4))^2)
b=√((4+2)^2+(-4+4)^2)
b=√(6^2+0)
b=6units

Consider the points (4,4) and (4,-4).


Substitute\text{ }x_2=4,x_1=4,y_2=-4,\text{ and }y_1=4\text{ in the distance formula.}


h=√((4-4)^2+(-4-4)^2)
h=√(0+8^2)
h=8units

Consider the area of the trapezoid formula.


A=(a+b)/(2)h

Substitute a = 9 units, b = 6 units, and h =8 units in the formula.


A=(9+6)/(2)\cdot8
A=15\cdot4
A=60units^2

Final answer:

The area of a polygon is 60 square units.

What is the area of a polygon with vertices of (-2, -4), (4, -4), (4, 4), and (-5, 4)?thank-example-1
User Cfranklin
by
3.3k points