Question

Is (-1, 6, -2) a solution to the system below?

3x+y+z=1
2x-y-5z = -2
-× +4y + 6z = -11

Answer 1

No, (-1, 6, -2) is not a solution to the system of equations.

Step-by-step explanation:

To determine if (-1, 6, -2) is a solution to the system, we substitute the values of x, y, and z into each equation and check if the equations are satisfied:

1. For the first equation, substitute x = -1, y = 6, and z = -2:
   3(-1) + 6 + (-2) = -3 + 6 - 2 = 1 = 12 (not satisfied)
2. For the second equation, substitute x = -1, y = 6, and z = -2:
   2(-1) - 6 - 5(-2) = -2 - 6 + 10 = 2 = -2 (not satisfied)
3. For the third equation, substitute x = -1, y = 6, and z = -2:
   -1 + 4(6) + 6(-2) = -1 + 24 - 12 = 11 = -11 (not satisfied)

Since (-1, 6, -2) does not satisfy any of the equations, it is NOT a solution to the system.