The calculated value of x in sin²(x) + 6sin(x) + 5 = 0 is 270 degrees
How to determine the value of x
From the question, we have the following parameters that can be used in our computation:
sin²(x) + 6sin(x) + 5 = 0
When expanded, we have
sin²(x) + sin(x) + 5sin(x) + 5 = 0
This gives
(sin(x) + 5)(sin(x) + 1) = 0
When expanded, we have
sin(x) + 5 = 0 and sin(x) + 1 = 0
So, we have
sin(x) = -5 and sin(x) = -1
This gives
x = 270 degrees
Hence, the value of x is 270 degrees
Question
Calculate the value of x in degrees for sin^(x) + 6sin(x) + 5 = 0