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Pieces of potassium (Φ = 3.68 × 10^–19 J) and sodium (Φ = 4.41 ×10^–19 J) metal are exposed to radiation of wavelength 300.0 nm. What is the velocity of the electrons from potassium and Sodium?

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Final answer:

To calculate the velocity of electrons from potassium and sodium when exposed to radiation, use the equation v = c * (1 - Φ/E), where v is the velocity of the electrons, c is the speed of light, Φ is the work function of the metal, and E is the energy of the radiation. By substituting the given values, the velocities can be calculated.

Step-by-step explanation:

In order to calculate the velocity of electrons from potassium and sodium, we need to use the equation:

v = c * (1 - Φ/E)

Where:

  • v is the velocity of the electrons
  • c is the speed of light (3.0 imes 10^8 m/s)
  • Φ is the work function of the metal
  • E is the energy of the radiation

For potassium (Φ = 3.68 imes 10^-19 J) and a radiation wavelength of 300.0 nm, we can calculate the energy (E) using the equation:

E = hc/λ

Where:

  • E is the energy of the radiation
  • h is Planck's constant (6.63 imes 10^-34 J·s)
  • c is the speed of light (3.0 imes 10^8 m/s)
  • λ is the wavelength of the radiation

Similarly, for sodium (Φ = 4.41 imes 10^-19 J) and a radiation wavelength of 300.0 nm, we can calculate the energy (E).

Substituting the values into the equation, we can calculate the velocity of the electrons for potassium and sodium.

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