Final answer:
In the Hershey-Chase experiment, radioactive phosphorus 32P, marking DNA, was found in the pellet with the bacteria, while radioactive sulfur 35S, marking proteins, was in the supernatant. This demonstrated that DNA is the genetic material. Hence, the correct distribution of radioactivity was 32P in the pellet, 35S in the solution.
Step-by-step explanation:
Alfred Hershey and Martha Chase designed a pivotal experiment in 1952 to identify the genetic material responsible for heredity within T2 bacteriophages when infecting E. coli bacteria. By utilizing radioactive isotopes, 32P marked DNA and 35S marked proteins due to phosphorous being exclusive to DNA and sulfur being prevalent in proteins. After the bacteriophages infected the E. coli and the mixture underwent centrifugation, Hershey and Chase observed that the 32P was in the pellet with the bacteria, and the 35S was in the supernatant with the empty virus heads.
This indicated that DNA, not protein, was the material injected into the E. coli cells and was therefore the genetic material responsible for heredity. Thus, the correct answer to their experiment's expected outcome is A. 32P in the pellet, 35S in the solution, which is where the researchers would have seen the distribution of radioactivity after centrifugation.