Question

There are two programs in your current working directory, mefirst and thenme. What yould you type (on a single line) to invoke mefirst, wait for it to complete, then invoke thenme?

Answer 1

Use './mefirst && ./thenme' to execute 'mefirst' and, upon its successful completion, then execute 'thenme' in a Unix-like terminal.

Step-by-step explanation:

To invoke mefirst, wait for it to complete, and then invoke thenme all on a single command line, you can use the following syntax:./mefirst && ./thenmeThis line makes use of the logical AND operator '&&' which ensures that the second command, thenme, is only executed if the first command, mefirst, exits successfully (with a return status of 0). This is a common pattern in shell scripting and command-line execution to ensure that a sequence of programs or scripts are run in order.

To invoke the program 'mefirst' and wait for it to complete before invoking 'thenme', you can use the following command in your terminalmefirst ; thenmeThis command will execute 'mefirst', wait for it to finish, and then proceed to execute 'thenme'. The semicolon (;) acts as a command separator, instructing the terminal to wait until the first command finishes before running the second one. This ensures sequential execution of the two programs.