Question

The drawing shows a uniform electric field that points in the negative y direction; the magnitude of the field is 3190 N/C. Determine the electric potential difference the following points.

Answer 1

(a) The magnitude of the electric potential between point B and point A is 191.4 V.

(b) The magnitude of the electric potential between point C and point B is 255.2 V.

(c) The magnitude of the electric potential between point A and point C is 319 V.

How to calculate the magnitude of the electric potential?

(a) The magnitude of the electric potential between point B and point A is calculated as;

V = Er

where;

• E is the magnitude of the electric field
• r is the distance

`V_B - V_A` = 3190 N/C x 0.06 m

`V_B - V_A` = 191.4 V

(b) The magnitude of the electric potential between point C and point B is calculated as;

`V_C - V_B` = 3190 N/C x 0.08 m

`V_C - V_B` = 255.2 V

(c) The magnitude of the electric potential between point A and point C is calculated as;

`V_A - V_C` = 3190 N/C x 0.1 m

`V_A - V_C` = 319 V