Question

Let be 0 an angle in quadrant I such that tqn0

Answer 1

`\begin{gathered} \cos \theta=(4)/(5) \\ \csc \theta=(5)/(3) \end{gathered}`

Explanation:

Quadrant 1 on a coordinate plane is the one at the right top corner, therefore the tangent of an angle equals 3/4, would be:

Then, the cos and csc of the same angle would be:

`\begin{gathered} \cos \theta=\frac{\text{ adjacent}}{\text{hypotenuse}} \\ \cos \theta=\frac{4}{\sqrt[]{4^2+3^2}} \\ \cos \theta=(4)/(5) \end{gathered}`

For csc theta:

`\begin{gathered} \csc \theta=(1)/(\sin \theta) \\ \csc \theta=\frac{hypotenuse}{\text{ opposite}} \\ \csc \theta=(5)/(3) \end{gathered}`