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The reaction used to produce solid iron ore is below. Fe2O3 (s) + 3CO (g) à 2Fe (s) + 3CO2 (g) The reaction of Fe2O3 with CO has a theoretical yield of 129 grams solid Fe. In the laboratory, your reaction
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The reaction used to produce solid iron ore is below.

Fe2O3 (s) + 3CO (g) à 2Fe (s) + 3CO2 (g)

The reaction of Fe2O3 with CO has a theoretical yield of 129 grams solid Fe. In the laboratory, your reaction produces 87.4 grams of solid Fe. What is the percent yield?

User Dinkar Kumar
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1 Answer

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% yield = (actual yield / theoretical yield) x100
(87.4 / 129) x100 = 67.75%
User Harshad Kavathiya
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