Final answer:
The molarity of the solution formed by dissolving 468mg of MgI₂ in enough water to yield 50.0mL of solution is 0.0336 M.
Step-by-step explanation:
To determine the molarity of a solution, we need to use the formula:
Molarity (M) = moles of solute / volume of solution (in L)
First, we need to convert the mass of MgI₂ to moles. The molar mass of MgI₂ is 278.113 g/mol. Therefore, 468 mg is equal to 0.468 g, which is 0.468/278.113 = 0.00168 moles of MgI₂.
The volume of the solution is given as 50.0 mL, which is 0.050 L. Plugging the values into the formula:
Molarity (M) = 0.00168 moles / 0.050 L = 0.0336 M