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\[p(x)=2x^3+3x^2-18x-27\]

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The roots of the cubic equation 2x³ + 3x² - 18x - 27 are x = -3, 3, -3/2.

How to find roots of polynomial.

For p(x) = 2x³ + 3x² - 18x - 27 the possible rational roots are +- 1, +-3, +-9, +- 27.

By trying these values, we can find that x = -3 is a root.

p(-3) = 2(-3)³ + 3(-3)² - 18(-3) - 27

= -54 + 27 + 54 -27

= 0

Therefore, x + 3 is a factor.

Division 2x³ + 3x² - 18x - 27 by x + 3 to find the other factor.

(2x³ + 3x² - 18x - 27)/( x + 3)

= 2x² - 3x - 9.

Factor the quadratic 2x² - 3x - 9.

(x - 3)(2x + 3)

x = 3 or -3/2

So, the roots of the original cubic equation 2x³ + 3x² - 18x - 27 are x = -3, 3, -3/2.

\[p(x)=2x^3+3x^2-18x-27\]-example-1
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