Question

using a remote 6 m long, workers apply input force of 1250 N to move a 2000 N crate onto a platform 2 m high. What is the efficiency of the ramp?

Answer 1

The efficiency of the ramp is approximately 53.33%, calculated by comparing the work output (gravitational potential energy gained by the crate) to the work input (force applied by the workers along the ramp).

Step-by-step explanation:

To calculate the efficiency of the ramp, we need to compare the work output with the work input. The work output is the gravitational potential energy gained by the crate when it is lifted to a height of 2 meters, while the work input is the force applied by the workers along the 6-meter ramp.

The gravitational potential energy (Work output) gained by the crate can be calculated as:

Work output = force due to gravity x height
= 2000 N x 2 m
= 4000 Joules

The work input is the force applied by the workers times the distance of the ramp:

Work input = applied force x distance of ramp
= 1250 N x 6 m
= 7500 Joules

Efficiency is calculated using the following formula:

Efficiency = (Work output / Work input) x 100%
= (4000 J / 7500 J) x 100%
= ~53.33%

Therefore, the efficiency of the ramp is approximately 53.33%.