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If Q = 25 μC, q = 10 μC, and L = 40 cm, what is the magnitude of the electrostatic force on q?

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Final answer:

The magnitude of the electrostatic force can be calculated using Coulomb's law, and it is approximately 225 x 10^6 N.

Step-by-step explanation:

The magnitude of the electrostatic force on charge q can be calculated using Coulomb's law:

F = k * |Q * q| / L^2

Where:

  • F is the magnitude of the electrostatic force
  • k is the electrostatic constant (approximately 9 x 10^9 Nm^2/C^2)
  • Q is the charge of the first object (25 μC)
  • q is the charge of the second object (10 μC)
  • L is the distance between the charges (40 cm)

Substituting the given values:

F = (9 x 10^9 Nm^2/C^2) * |25 μC * 10 μC| / (40 cm)^2

F = (9 x 10^9 Nm^2/C^2) * (250 μC^2) / (0.4 m^2)

F ≈ 225 x 10^6 N

User Morten Bork
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