Question

Determine if the given ordered triple is a solution of the system. Show all work.

Answer 1

5, -3 and -2

So:

`\begin{gathered} x+y+z=0 \\ 5+(\text{ -}3)+\text{ \lparen-}2)=0\text{ } \\ 5\text{ - 3 - 2 = 0} \\ 0=0 \\ \\ \\ x+2y\text{ -}3z=5 \\ 5+2(\text{ -3\rparen - 3\lparen -2\rparen=5} \\ 5\text{ - }6\text{ + 6= 5} \\ 5=5 \\ \\ 3x+4y+2z=\text{ -}1 \\ 3(5)\text{ + 4\lparen -3\rparen + 2\lparen -2\rparen = -1} \\ 15\text{ - 12 -4= -1} \\ \text{ -1= -1} \end{gathered}`

All equations are correct, so (5,-3,-2) is a solution to the system.