Answer:
5 in by 8 in
Explanation:
Given that :
Area, A of rectangle = 40 in²
Let
height = x
Base = 2x - 2
Area of rectangle = L * B
40 = x * (2x - 2)
40 = 2x² - 2x
2x² - 2x - 40 = 0
x² - x - 20 = 0
x² - 5x + 4x - 20 =0
x(x - 5) +4(x - 5) = 0
x - 5 = 0 or
x + 4 = 0
x = 5 or x = - 4
X cannot be negative
X = 5
Height = 5
Base = 2*5 - 2 = 8