Question

I need help with questions

Answer 1

B. The zeros are -2/3 and -3 because y=(3x+2)(x+3)

Step-by-step explanation:

Given the equation:

`y=3x^2+11x+6`

To find the zeros, first, factorize the expression:

`\begin{gathered} y=3x^2+9x+2x+6 \\ y=3x(x+3)+2(x+3) \\ y=(3x+2)(x+3) \end{gathered}`

Next, set the factored expression equal to 0.

`\begin{gathered} y=(3x+2)(x+3)=0 \\ \implies3x+2=0\text{ or }x+3=0 \\ 3x=-2\text{ or }x=-3 \\ x=-(2)/(3)\text{ or }x=-3 \end{gathered}`

Thus, the zeros are -2/3 and -3 because y=(3x+2)(x+3).

The correct choice is B.