Final answer:
To calculate the frequencies of aB and ab under linkage equilibrium without additional data, it is not possible. Linkage equilibrium suggests that the frequencies of aB and ab are products of the frequencies of their alleles. However, with only the frequencies of gAB and gAb provided, and without the frequency of allele B, an exact calculation cannot be made.
Step-by-step explanation:
To find the frequencies of aB and ab chromosomes under the assumption that loci A and B are in linkage equilibrium, we must first understand the definition of linkage equilibrium and how allele frequencies relate to haplotype frequencies. Linkage equilibrium occurs when the genotype at one locus is independent of the genotype at another locus; thus, the frequency of each haplotype is the product of the frequencies of its constituent alleles.
Calculation of allele frequencies
Given that gAB = 0.24 and gAb = 0.06, we can calculate the frequency of alleles A and B by summing the frequencies of the haplotypes that contain these alleles:
- Frequency of A = gAB + gAb = 0.24 + 0.06 = 0.3
- Frequency of a = 1 - Frequency of A = 1 - 0.3 = 0.7
- Frequency of B = gAB + frequency of aB (unknown)
- Frequency of b = gAb + frequency of ab (unknown)
Since loci A and B are in linkage equilibrium, we can determine the frequencies of aB and ab by multiplying the frequencies of the individual alleles:
- Frequency of aB = (Frequency of a) * (Frequency of B)
- Frequency of ab = (Frequency of a) * (Frequency of b)
To find the exact values for the frequencies of B and b, we need additional information, such as the frequency of allele B or the frequency of the gBB or gbb genotypes. Without such information, we cannot provide the requested frequencies.