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If one were to double the amount of enzyme in a reaction with an initial ΔG of -5 kcal/mole, what would the ΔG be?

User Jazzy
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Final answer:

If one were to double the amount of enzyme in a reaction with an initial ΔG of -5 kcal/mole, the ΔG value would remain the same.

Step-by-step explanation:

The change in free energy (ΔG) of a reaction can be calculated using the equation ΔG˚ = -RT ln K, where ∆G˚ is the standard free energy change, R is the gas constant, T is the temperature in Kelvin, and K is the equilibrium constant.

If the initial ΔG is -5 kcal/mole and the amount of enzyme is doubled, the ΔG value remains the same.

User Fokwa Best
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