Final answer:
To find the number of grams in 1.11 moles of manganese sulfate, you need to calculate the molar mass of manganese sulfate and then multiply it by the number of moles. Mass = 1.11 moles * 150.998 g/mol = 167.688 g
Step-by-step explanation:
To determine the number of grams in 1.11 moles of manganese sulfate, we need to know the molar mass of manganese sulfate. The molar mass of manganese sulfate (MnSO4) can be found by adding up the atomic masses of each element: Mn (54.938 g/mol), S (32.06 g/mol), and O (16.00 g/mol) four times (since there are four oxygen atoms). The molar mass of manganese sulfate is therefore:
(54.938 g/mol) + (32.06 g/mol) + (16.00 g/mol * 4) = 54.938 g/mol + 32.06 g/mol + 64.00 g/mol = 150.998 g/mol
So, 1 mole of manganese sulfate weighs 150.998 grams. To find the mass of 1.11 moles of manganese sulfate, we can use the formula:
Mass (in grams) = Number of moles * Molar mass
Mass = 1.11 moles * 150.998 g/mol = 167.688 g