155k views
1 vote
How many moles of CCl₄ are present in 28.3 g of the compound? Express your answer to 3 significant figures.

User DenMark
by
7.8k points

1 Answer

3 votes

Final answer:

To determine the number of moles of CCl4 in 28.3 grams, the molar mass of CCl4 is used as a conversion factor, resulting in approximately 0.184 moles, when expressed to three significant figures.

Step-by-step explanation:

To find out how many moles of CCl4 are present in 28.3 g of the compound, we need to use the molar mass of CCl4 as a conversion factor. The molar mass of CCl4 (= 12.01 g/mol for Carbon + (4 * 35.45 g/mol) for Chlorine) is approximately 153.81 g/mol.

Now, to convert grams to moles, we use the formula:

moles of CCl4 = mass (g) / molar mass (g/mol)

moles of CCl4 = 28.3 g / 153.81 g/mol

moles of CCl4 = 0.184 moles (to 3 significant figures)

User Aray Karjauv
by
7.0k points