Question

How many moles of Na⁺ ions are present in 37 mL of a 0.415 M Na₂SO₄ solution?

Answer 1

To determine the number of moles of Na⁺ ions in the solution, we need to calculate the number of moles of Na₂SO₄ and then multiply it by 2.

Step-by-step explanation:

To determine the number of moles of Na⁺ ions in the solution, we first need to calculate the number of moles of Na₂SO₄. The molar concentration of Na₂SO₄ is given as 0.415 M, which means there are 0.415 moles of Na₂SO₄ in 1 liter of solution. Since the volume of the solution is given as 37 mL, we can convert it to liters by dividing by 1000: 37 mL ÷ 1000 = 0.037 L.

To calculate the number of moles of Na₂SO₄, we can use the equation:

Moles = concentration × volume

So, Moles of Na₂SO₄ = 0.415 M × 0.037 L = 0.015355 mol

Since each Na₂SO₄ molecule contains 2 moles of Na⁺ ions, we can multiply the number of moles of Na₂SO₄ by 2 to get the number of moles of Na⁺ ions in the solution: 0.015355 mol × 2 = 0.03071 mol