Question

Consider the reaction represented by the (unbalanced) equation: NH₃ + O₂ → NO + H₂O. For every 2.00 mol of NH₃ that reacts, how many moles of O₂ are required?

Answer 1

For every 2.00 mol of NH3, 2.50 mol of O2 are required for the reaction, according to the balanced chemical equation which sets the molar ratio of NH3 to O2 as 4:5.

Step-by-step explanation:

To calculate the amount of O2 required to react with 2.00 mol of NH3, we first need to look at the balanced equation, which is given as 4NH3(g) + 5O2(g) → 4NO(g) + 6H2O(l). Now, let's determine the molar ratio between NH3 and O2 from the balanced equation: for every 4 mol of NH3 that react, 5 mol of O2 are required.

Therefore, since we have half the molar amount of NH3 (2.00 mol instead of 4 mol), we would require half the molar amount of O2 stated in the equation. Half of 5 mol is 2.50 mol. So for every 2.00 mol of NH3, 2.50 mol of O2 are required for the reaction to proceed.