Final answer:
Dissolving iron(III) chloride (FeCl3) results in four particles per mole, taking into account the van't Hoff factor (i) of 4. For 0.170 mol of FeCl3, there will be 0.680 mol of dissolved particles in the solution.
Step-by-step explanation:
When iron(III) chloride (FeCl3) dissolves in water, it dissociates into four particles: one iron(III) ion (Fe3+) and three chloride ions (Cl−). This is represented by the following dissociation equation:
FeCl3 → Fe3+ + 3Cl−
The dissolution of ionic compounds like FeCl3 leads to an increase in the number of particles in solution because each mole of the compound produces more than one mole of ions. For FeCl3, the van't Hoff factor (i) is 4. Thus, if you have 0.170 mol of FeCl3, you will have 0.170 mol × 4 = 0.680 mol of particles in the solution.