Question

Suppose you react 11.12 grams of MnO₂ according to the following (unbalanced) equation: HCl + MnO₂ → H₂O + MnCl₂ + Cl₂. How many moles of manganese(IV) oxide do you have?

Answer 1

To determine the number of moles of manganese(IV) oxide, divide the mass of MnO2 by its molar mass. The molar mass of MnO2 is 86.94 g/mol.

Step-by-step explanation:

To determine the number of moles of manganese(IV) oxide, we need to convert the mass of MnO₂ to moles using its molar mass. The molar mass of MnO₂ is the sum of the atomic masses of one manganese (Mn) atom and two oxygen (O) atoms. The atomic mass of Mn is 54.94 g/mol and the atomic mass of O is 16.00 g/mol. Therefore, the molar mass of MnO₂ is (54.94 + 16.00 + 16.00) g/mol = 86.94 g/mol.

To convert the mass of MnO₂ (11.12 grams) to moles, we use the equation:

moles = mass / molar mass

moles = 11.12 g / 86.94 g/mol = 0.1279 moles

Therefore, you have 0.1279 moles of manganese(IV) oxide.