Question

Rosetta averages 148 points per bowling game with a standard deviation of 14 points. Suppose Rosetta's points perbowling game are normally distributed. Let X = the number of points per bowling game. Then X ~ N(148, 14).If necessary, round to three decimal places.

Answer 1

The z-score is given by the following equation:

`z=(x-\mu)/(\sigma)`

Where:

Replacing the values for x = 110:

`z=(110-148)/(14)`

Solving the operations:

`z=-2.71`

This means that x = 110 is -2.71 standard deviations to the left of the mean. The mean is given as 148.