The calculated value of x in the equation 7 + 4 log₂(x − 9) = 27 is 41
How to determine the value of x in the equation
From the question, we have the following parameters that can be used in our computation:
7 + 4 log₂(x − 9) = 27
Subtract 7 from both sides of the equation
So, we have
4 log₂(x − 9) = 20
Divide through by 4
log₂(x − 9) = 5
Next, we have
x - 9 = 2⁵
This gives
x = 2⁵ + 9
Evaluate
x = 41
Hence, the value of x in the equation is 41
Question
Solve for x in 7 + 4 log_(2) (x − 9) = 27.