Step-by-step explanation:
Oxygen gas is reacted with excess hydrogen gas to produce water according to the following equation.
2 H₂ + O₂ ---> 2 H₂O
We have to find the number of molecules of water that are produced when 8.93 * 10^23 molecules of oxygen are reacted.
First we have to convert the molecules of oxygen gas into moles using Avogadro's number. We know that there are 6.022 *10^23 molecules of oxygen in 1 mol of oxygen gas.
1 mol of O₂ = 6.022 *10^23 molecules.
moles of O₂ = 8.93 * 10^23 molecules * 1 mol/(6.022 *10^23 molecules)
moles of O₂ = 1.48 mol
2 H₂ + O₂ ---> 2 H₂O
Now, if we pay attention to the coefficients of the equation, we will see that 2 moles of H₂ will react with 1 mol of O₂ to produce 2 moles of H₂O. That means that the molar ratio between O₂ and H₂O is 1 to 2. We can use that relationship to find the number of moles of H₂O that will be produced by 1.48 moles of O₂ when reacting with excess H₂.
1 mol of O₂ : 2 moles of H₂O molar ratio
moles of H₂O = 1.48 moles of O₂ * 2 moles of H₂O/(1 mol of O₂)
moles of H₂O = 2.96 moles
And finally we can convert the moles of H₂O back to molecules using Avogadro's number again.
1 mol of H₂O molecules = 6.022 * 10^23 molecules
H₂O molecules = 2.96 moles * 6.022 *10^23 molecules/(1 mol)
H₂O molecules = 1.79 * 10^24 molecules
Answer: 1.79 * 10^24 molecules